Write a program to simulate a dictionary using linked list.

Write a program to simulate a dictionary using linked list.

Code for Program to simulate a dictionary using linked list in C Programming

#include <stdio.h>
#include <conio.h>
#include <malloc.h>
#include <stdlib.h>
#include <string.h>
#include <ctype.h>

struct node
{
    char data [ 20 ] ;
    char m [ 5 ] [ 20 ] ;
    int mcount ;
    struct node * link ;
} ;

struct node * dic [ 26 ] ;

void add ( char * ) ;
int  search ( char * ) ;
void show( ) ;
void deldic( ) ;

void main( )
{
    char word [ 20 ] , ch ;
    int i ;

    clrscr( ) ;

    while ( 1 )
    {
        clrscr( ) ;
        printf ( "\n\t\tDictionary\n" ) ;
        printf ( "\n\t\t1.Add Word.\n" ) ;
        printf ( "\t\t2.Search Word.\n" ) ;
        printf ( "\t\t3.Show Dictionary.\n" ) ;
        printf ( "\t\t0.Exit." ) ;
        printf ( "\n\n\t\tYour Choice ") ;
        scanf ( "%d", &ch ) ;

        switch ( ch )
        {
            case 1 :

                printf ( "\nEnter any word : " ) ;
                fflush ( stdin ) ;
                gets ( word ) ;
                add ( word ) ;

                break ;

            case 2 :

                printf ( "\nEnter the word to search : " ) ;
                fflush ( stdin ) ;
                gets ( word ) ;
                i = search ( word ) ;
                if ( ! i )
                    printf ( "Word does not exists." ) ;
                getch( ) ;

                break ;

            case 3 :

                show( ) ;
                getch( ) ;

                break ;

            case 0 :

                deldic( ) ;
                exit ( 0 ) ;

            default :

                printf ( "\nWrong Choice" ) ;
        }
    }
}

void add ( char * str )
{
    int i, j = toupper ( str [ 0 ] ) - 65 ;
    struct node * r, * temp = dic [ j ], * q ;
    char mean [ 5 ] [ 20 ], ch = 'y' ;

    i = search ( str ) ;
    if ( i )
    {
        printf ( "\nWord already exists." ) ;
        getch( ) ;
        return ;
    }
    q = ( struct node * ) malloc ( sizeof ( struct node ) ) ;
    strcpy ( q -> data, str ) ;
    q -> link = NULL ;

    for ( i = 0 ; tolower ( ch ) == 'y' && i < 5 ; i++ )
    {
        fflush ( stdin ) ;
        printf ( "\n\nEnter the meaning(s) : " ) ;
        gets ( mean [ i ] ) ;
        strcpy ( q -> m [ i ] , mean [ i ] ) ;
        if ( i != 4 )
            printf ( "\nAdd more meanings (y/n) " ) ;
        else
            printf ( "You cannot enter more than 5 meanings." ) ;
        fflush ( stdin ) ;
        ch = getche( ) ;
    }

    q -> mcount = i ;
    if ( dic [ j ] == NULL || strcmp ( dic [ j ] -> data, str ) > 0 )
    {
        r = dic [ j ] ;
        dic [ j ] = q ;
        q -> link = r ;
        return ;
    }

    else
    {
        while ( temp != NULL )
        {
            if ( ( strcmp ( temp -> data, str ) < 0 ) && ( ( strcmp ( temp -> link -> data, str ) > 0 ) ||
                                            temp -> link == NULL ) )
            {
                q -> link = temp -> link ;
                temp -> link = q ;
                return ;
            }
            temp = temp -> link ;
        }
    }
}

int search ( char *str )
{
    struct node *n ;
    char temp1 [ 20 ] ;
    char temp2 [ 20 ] ;
    int i ;

    n = dic [ toupper ( str [ 0 ] ) - 65 ] ;
    strcpy ( temp2, str ) ;
    strupr ( temp2 ) ;

    while ( n != NULL )
    {
        strcpy ( temp1, n -> data ) ;

        if (  strcmp ( strupr ( temp1 ), temp2 ) == 0 )
        {
            printf ( "\n%s\t\t%s", n -> data, n -> m [ 0 ] ) ;
            for ( i = 1 ; i < n -> mcount ; i++ )
                printf ( "\n\t\t%s", n -> m [ i ] ) ;
            return 1 ;
        }
        n = n -> link ;
    }
    return 0 ;
}

void show( )
{
    struct node *n ;
    int i, j ;

    printf ( "Word\t\tMeaning\n" ) ;
    for ( i = 0 ; i <= 30 ; i++ )
        printf ( "-" ) ;


    for ( i = 0 ; i <= 25 ; i++ )
    {
        n = dic [ i ] ;
        while ( n != NULL )
        {
            printf ( "\n%s\t\t%s", n -> data, n -> m [ 0 ] ) ;
            for ( j = 1 ; j < n -> mcount ; j++ )
                printf ( "\n\t\t%s", n -> m [ j ] ) ;
            n = n -> link ;
        }
    }
}

void deldic( )
{
    struct node *n, *t ;
    int i ;

    for ( i = 0 ; i <= 25 ; i++ )
    {
        n = dic [ i ] ;
        while ( n != NULL )
        {
            t = n -> link ;
            free ( n ) ;
            n = t ;
        }
    }
}